| ps | |
|---|---|
| 링크 | acmicpc.net/… |
| 출처 | BOJ |
| 문제 번호 | 11438 |
| 문제명 | LCA 2 |
| 레벨 | 플래티넘 5 |
| 분류 |
LCA |
| 시간복잡도 | O(n+qlogn) |
| 인풋사이즈 | n<=100,000, q<=100,000 |
| 사용한 언어 | Python |
| 제출기록 | 57828KB / 740ms |
| 최고기록 | 740ms |
| 해결날짜 | 2022/12/01 |
"""Solution code for "BOJ 11438. LCA 2".
- Problem link: https://www.acmicpc.net/problem/11438
- Solution link: http://www.teferi.net/ps/problems/boj/11438
Tags: [LCA]
"""
import sys
from teflib import tree as ttree
ROOT = 0
def main():
N = int(sys.stdin.readline())
tree = [[] for _ in range(N)]
for _ in range(N - 1):
u, v = [int(x) for x in sys.stdin.readline().split()]
tree[u - 1].append(v - 1)
tree[v - 1].append(u - 1)
lca = ttree.LowestCommonAncestor(tree, ROOT)
M = int(sys.stdin.readline())
for _ in range(M):
u, v = [int(x) for x in sys.stdin.readline().split()]
print(lca.lca_node(u - 1, v - 1) + 1)
if __name__ == '__main__':
main()